Find the value of $2^{3 - {log}_{2} 3}$

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Solution

Given, $2^{3 - {log}_{2} 3}$

$= 2^{3} 2^{- {log}_{2} 3}$

$= 8 \times 2^{{log}_{2} \frac{1}{3}}$

$= 8 \times \frac{1}{3} = \frac{8}{3}$

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