Find the value of 23 - 53 - 70-

(2^3 × 5^3 × 7^0) = (2^3 × 5^3 × 1) (Since, 7^0 = 1) = (2^3 × 5^3 ) = nbsp;(2 × 5)^3 nbsp;(Since, a^m × b^m = (ab)^m) = nbsp;(10)^3 nbsp; = nbsp;1000 ...

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Byju's Answer

Standard VIII

Mathematics

Division of Exponents Having the Same Base

Find the valu...

Question

Find the value of $(2^{3} \times 5^{3} \times 7^{0})$ .

1000

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100

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700

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343

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Solution

The correct option is A 1000
$(2^{3} \times 5^{3} \times 7^{0})$
= $(2^{3} \times 5^{3} \times 1)$ $(S i n c e, 7^{0} = 1)$
= $(2^{3} \times 5^{3})$
= ${(2 \times 5)}^{3}$ $(S i n c e, a^{m} \times b^{m} = {(a b)}^{m})$
= ${(10)}^{3}$
= $1000$

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Similar questions

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{(\frac{5}{3})}^{- 4} \times {(\frac{5}{3})}^{- 5} = {(\frac{5}{3})}^{3 x} .

51 + 52 + 53 + ……. + 70

Q. Find the value of

(2^{3} \times 5^{3} \times 7^{0})

Find the value of $5^{3} \times 2^{3}$ .

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∣ ∣ ∣ \begin{matrix} 5 & 3 - 7 & 0 \end{matrix} ∣ ∣ ∣

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Find the value of (23×53×70).

The correct option is A 1000(23×53×70) = (23×53×1) (Since,70=1) = (23×53) = (2×5)3 (Since,am × bm = (ab)m) = (10)3 = 1000

Find the value of $(2^{3} \times 5^{3} \times 7^{0})$ .

The correct option is A 1000
$(2^{3} \times 5^{3} \times 7^{0})$
= $(2^{3} \times 5^{3} \times 1)$ $(S i n c e, 7^{0} = 1)$
= $(2^{3} \times 5^{3})$
= ${(2 \times 5)}^{3}$ $(S i n c e, a^{m} \times b^{m} = {(a b)}^{m})$
= ${(10)}^{3}$
= $1000$