Find the value of 2-52-0-42

The correct option is D 1 The given expression is (2.5)^2 × (0.4)^2 = ( 25/10 )^2 × ( 4/10 )^2 =25 × 25/10 × 10×4 × 4/10 × 10 =625/100×16/100 =10,000/100 × 100 ...

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Standard VII

Mathematics

Perfect Square Numbers

Find the valu...

Question

Find the value of $(2.5)^{2} \times (0.4)^{2}$

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Solution

The correct option is A
1

The given expression is $(2.5)^{2} \times (0.4)^{2}$

$= {(\frac{25}{10})}^{2} \times {(\frac{4}{10})}^{2}$

$= \frac{25 \times 25}{10 \times 10} \times \frac{4 \times 4}{10 \times 10}$

$= \frac{625}{100} \times \frac{16}{100}$

$= \frac{10, 000}{100 \times 100}$

$= 1$

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Find the value of (2.5)2×(0.4)2

The correct option is A 1 The given expression is (2.5)2×(0.4)2 =(2510)2×(410)2 =25×2510×10×4×410×10 =625100×16100 =10,000100×100 =1

Find the value of $(2.5)^{2} \times (0.4)^{2}$

The correct option is A
1

The given expression is $(2.5)^{2} \times (0.4)^{2}$

$= {(\frac{25}{10})}^{2} \times {(\frac{4}{10})}^{2}$

$= \frac{25 \times 25}{10 \times 10} \times \frac{4 \times 4}{10 \times 10}$

$= \frac{625}{100} \times \frac{16}{100}$

$= \frac{10, 000}{100 \times 100}$

$= 1$