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Question

Find the value of (-2a2)×(-3b2)×(-4c2)×abc


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Solution

Multiplication of algebraic expressions

We know that,

Product of two monomials = (Product of their numerical coefficients) × (Product of their literal coefficients)

Therefore,

(-2a2)×(-3b2)×(-4c2)×abc=(-2×-3×-4)(a2×b2×c2)=-24a2b2c2

Therefore, value of given expression -24a2b2c2


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