Question

Find the value of $20+{\left(27\right)}^{\frac{-1}{3}}$

Answer 1

$20+(27{)}^{-1/3}$

$=20+\frac{1}{(27{)}^{1/3}}20+\frac{1}{(3{)}^{3\times 1/3}}$

$=20+\frac{1}{3}$

$=\frac{60+1}{3}$

$=\frac{61}{3}$