Find the value of -24 x 2 y 2 x -3 y when- x -2 and y -3-A- 1252B- 1440C- 1550D- 1456

The correct option is B 1440 24x^2y(2x 3y) = 24x^2y× 2x + 24x^2y× 3y = 48x^3y + 72x^2y^2 Substituting the value of x = 2 and y = 3, = 48(2)^3(3) + 72(2)^2( ...

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Byju's Answer

Standard VIII

Mathematics

Multiplication of a Binomial by a Monomial

Find the valu...

Question

Find the value of $- 24 x^{2} y (2 x - 3 y)$ when, $x = 2$ and $y = 3$ .

1252

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1440

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1550

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1456

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Solution

The correct option is B 1440
$- 24 x^{2} y (2 x - 3 y)$
$= - 24 x^{2} y \times 2 x + 24 x^{2} y \times 3 y$
$= - 48 x^{3} y + 72 x^{2} y^{2}$
Substituting the value of $x = 2$ and $y = 3$ ,
$= - 48 (2)^{3} (3) + 72 (2)^{2} (3)^{2} = - 1152 + 2592 = 1440$

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Find the value of −24x2y(2x−3y) when, x=2 and y=3.

The correct option is B 1440−24x2y(2x−3y) =−24x2y×2x+24x2y×3y =−48x3y+72x2y2 Substituting the value of x=2 and y=3, =−48(2)3(3)+72(2)2(3)2=−1152+2592=1440

Find the value of $- 24 x^{2} y (2 x - 3 y)$ when, $x = 2$ and $y = 3$ .

The correct option is B 1440
$- 24 x^{2} y (2 x - 3 y)$
$= - 24 x^{2} y \times 2 x + 24 x^{2} y \times 3 y$
$= - 48 x^{3} y + 72 x^{2} y^{2}$
Substituting the value of $x = 2$ and $y = 3$ ,
$= - 48 (2)^{3} (3) + 72 (2)^{2} (3)^{2} = - 1152 + 2592 = 1440$