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Question

Find the value of 27(1log43)+16log42+3(4log79)


A

64

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B

68

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C

117

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D

49

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Solution

The correct option is C

117


27(1log43)+16log42+3(4log79)

=33log34+42log42+34log327
{1logba=logba}

=3log343+4log422+3(42)log37
As aloga(b)=b

So, 43 + 22 + 72
= 64+4+49=117


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