Find the value of 27(1log43)+16log42+3(4log79)
64
68
117
49
27(1log43)+16log42+3(4log79) =33log34+42log42+34log327 {1logba=logba} =3log343+4log422+3(42)log37 As aloga(b)=b
So, 43 + 22 + 72 = 64+4+49=117