Find the value of 27a^3+8b^3-125c^3 given that abc=0 and 3a+2b=5c.

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Solution

3a+2b=5c

(3a+2b-5c)^3=0^3

27a^3+8b^3-125c^3-3×3a×2b×5c=0

27a^3+8b^3-125c^3-90abc=0

so,

27a^3+8b^3-125c^3=0

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Similar questions

It is given that $3 a + 2 b = 5 c,$ then find the value of $27 a^{3} + 8 b^{3} - 125 c^{3}$ if $a b c = 0.$

If $3 a + 5 b + 4 c = 0$ , show that:
$27 a^{3} + 125 b^{3} + 64 c^{3} = 180 a b c$ .

27 a^{3} + 8 b^{3} - 18 a^{2} b - 12 a b^{2}

a^{3} - 8 b^{3} - 36 a b - 216

a = 2 b + 6

27 a^{3} - (3 a - b)^{3}

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