CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the value of 2a2a+7, if x4+2ax29=15 when x=2.

A
8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 8
Given x4+2ax29=15 at x=2.

let's first put the value of x=2 in the above equation.

24+2a×229=1516+8a9=158a+7=158a=8a=1

Now we have to find the value of 2a2a+7.
We already calculated value of a=1.
2×121+721+7=8

Hence, option 'a' is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
(x + a)(x +b)= x^2 + x(a+ b) + ab
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon