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Question

Find the value of 2a2a+7, if x4+2ax29=15 when x=2.

A
8
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B
6
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C
5
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D
10
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Solution

The correct option is A 8
Given x4+2ax29=15 at x=2.

let's first put the value of x=2 in the above equation.

24+2a×229=1516+8a9=158a+7=158a=8a=1

Now we have to find the value of 2a2a+7.
We already calculated value of a=1.
2×121+721+7=8

Hence, option 'a' is correct.

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