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Question

Find the value of 2n+1C0+2n+1C1+2n+1C2+......+2n+1Cn+2n+1Cn+1+2n+1Cn+2+.....+2n+1C2n+1 if n=3.
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Solution

We know,
Sum of the coefficients of binomial expansion
2n+1C0+2n+1C1+2n+1C2+......+2n+1Cn=2n
2n+1C0+2n+1C1+2n+1C2+......+2n+1Cn+2n+1Cn+1+2n+1Cn+2+.....+2n+1C2n+1=22n+1

Put n=3
26+1=27=128


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