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Question

Find the value of:
2p3q+4r8s when p=10,q=8,r=6 and s=2.

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Solution

Step: Finding the value of: 2p3q+4r8s
On substituting p=10,q=8,r=6 and s=2 in 2p3q+4r8s,
we get
2p3q+4r8s=(2×10)(3×8)+(4×6)(8×2)
=2024+2416
=2016
=4
Therefore, the value of 2p3q+4r8s is 4.

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