Find the value of: 2p−3q+4r−8swhenp=10,q=8,r=6ands=2.
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Solution
Step: Finding the value of: 2p−3q+4r−8s
On substituting p=10,q=8,r=6ands=2in2p−3q+4r−8s,
we get 2p−3q+4r−8s=(2×10)−(3×8)+(4×6)−(8×2) =20−24+24−16 =20−16 =4
Therefore, the value of 2p−3q+4r−8sis4.