Find the value of $(2 x + 5) (2 x - 5)$ .

4 x - 25

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4 x^{2} - 25

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2 x^{2} - 25

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4 x^{2} - 5

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Solution

The correct option is A $4 x^{2} - 25$
We know that binomial identities for $(x + y) (x - y) = x^{2} - y^{2}$
$∴ (2 x + 5) (2 x - 5) = (2 x)^{2} - 5^{2}$
$=$ $4 x^{2} - 25$

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Similar questions

Q. Tick (✓) the correct answer:
(2x + 5)(2x − 5) = ?
(a) (4x² + 25)
(b) (4x² − 25)
(c) (4x² − 10x + 25)
(d) (4x² + 10x − 25)

Tick $(✓)$ the correct answer in each of the following:
$(2 x + 5) (2 x - 5) = ?$
(a) $(4 x^{2} + 25)$
(b) $(4 x^{2} - 25)$
(c) $(4 x^{2} - 10 x + 25)$
(d) $(4 x^{2} + 10 x - 25)$

Q. State whether the statement is True or False:

(2 x - \frac{3}{5}) (2 x + \frac{3}{5})

is equal to

4 x^{2} - \frac{9}{25}

The equation of a circle passing through points of intersection of the circles $x^{2} + y^{2} + 13 x - 3 y = 0$ and

$2 x^{2} + 2 y^{2} + 4 x - 7 y - 25 = 0$ and point (1, 1) is

Find the equation whose roots are reciprocals of the roots of $2 x^{2} + 5 x + 4 = 0$ .

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Find the value of (2x+5)(2x−5).

The correct option is A 4x2−25We know that binomial identities for (x+y)(x−y)=x2−y2∴(2x+5)(2x−5)=(2x)2−52= 4x2−25

Find the value of $(2 x + 5) (2 x - 5)$ .

The correct option is A $4 x^{2} - 25$
We know that binomial identities for $(x + y) (x - y) = x^{2} - y^{2}$
$∴ (2 x + 5) (2 x - 5) = (2 x)^{2} - 5^{2}$
$=$ $4 x^{2} - 25$