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B
−90x2yz2
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C
−10x2yz2
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D
−10xyz
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Solution
The correct option is B−90x2yz2 On multiplying x with x, its power is raised to 2 i.e., x×x=x2
On multiplying z with z its power is also raised to 2 .
i.e., z×z=z2
Multiply all the coefficients to get 2×(−15)×3=−90
So, 2x×(−15yz)×3xz = −90x2yz2