Question

Find the value of.
$(3^0+4^{-1})\times 2^2$

Answer 1

We have,

$(3^0+4^{-1})\times 2^2$

So,

$(1+\frac{1}{4})\times 4$

$\Rightarrow \frac{5}{4}\times 4$

$\Rightarrow 5$

Hence, this is the answer.