Question

Find the value of ($3^0$ + $4^{-1}$) × $2^3$. ___

Answer 1

Given, ($3^0$ + $4^{-1}$) × $2^3$

Now, $4^{-1}$ = $\frac{1}{4}$ ($\because a^{-1}=$$\frac{1}{a}$),

and, $3^0$ = 1($\because a^0=1,wherea\ne 0$)

So, ($3^0$ + $4^{-1}$) × $2^2$ = (1+$\frac{1}{4})$× $2^3$

=$\frac{4+1}{4}\times 2^3$

=$5\times 2$

= $10$