Find the value of $(3^{- 1} + 4^{- 1} + 5^{- 1})^{0}$

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Solution

Any number raised to the power of $0$ equals to $1$ .
Hence $(3^{- 1} + 4^{- 1} + 5^{- 1})^{0} = 1$

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Similar questions

Question 3(iv)
Find the value of:

$\left(3^{-1}+4^{-1}+5^{-1}\right)^0$

\frac{10^{- 1} \times 5^{x - 3} \times 4^{x - 1}}{10 \times 5^{x - 5} \times 4^{x - 2}}

∣ ∣ ∣ \frac{1}{2} - 1 ∣ ∣ ∣ - ∣ ∣ ∣ \frac{2}{3} - 1 ∣ ∣ ∣ - ∣ ∣ ∣ \frac{3}{4} - 1 ∣ ∣ ∣ - ∣ ∣ ∣ \frac{4}{5} - 1 ∣ ∣ ∣

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