Find the value of $(3^{- 2})^{2}$ .

3^{- 4}

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2^{- 4}

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3^{0}

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3^{2}

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Solution

The correct option is A $3^{- 4}$
$(3^{- 2})^{2}$
We know, $(a^{m})^{n} = a^{m n} .$
$\Rightarrow (3^{- 2})^{2} = 3^{- 2 \times 2} = 3^{- 4}$

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