Question

Find the value of ($3^2$ + $4^{-1}$) $\times$ $2^2$

• A. 25
• B. 42
• C. 5
• D. 37

Answer 1

The correct option is D

37

Given , ($3^2$ + $4^{-1}$) $\times$ $2^2$,

$\Rightarrow$ $(9+\frac{1}{4}$) $\times$ $2^2$ ($\because a^{-m}=\frac{1}{a^m}$)

= $\frac{36+1}{4}$ $\times$ 4

= $\frac{37}{4}$ $\times$ 4

= 37