Find the value of 33- 32-

The correct options are A 3^5 D 243 Here the two terms have nbsp; nbsp;3^3 and 3^2 have different exponents, but the same base.Hence by adding the powers ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Multiplication of Powers with the Same Base

Find the valu...

Question

Find the value of $3^{3} \times 3^{2}$ .

$3^{5}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

343

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$3^{1}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

243

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A
$3^{5}$

D
243

Here the two terms have $3^{3}$ and $3^{2}$ have different exponents, but the same base.Hence by adding the powers we get,

$3^{3} \times 3^{2} = 3^{3 + 2}$ = $3^{5} = 243$

Suggest Corrections

Similar questions

Q. Find the value of

3^{2} \times 3^{4} \times 3^{3} = ?

Q. If

α = \frac{5}{2! 3} + \frac{5.7}{3! 3^{2}} + \frac{5.7.9}{4! 3^{3}}

,.... then find the value of

α^{2} + 4 α

Q. Value of

y = (0.36)^{{log}_{0.25} ⎛ ⎝ \frac{1}{3} + \frac{1}{3^{2}} + \frac{1}{3^{3}} + . . . \infty ⎞ ⎠}

Q. If the value of

{(1 + \frac{2}{3} + \frac{6}{3^{2}} + \frac{10}{3^{3}} + \dots upto \infty)}^{{log}_{(0.25)} ⎛ ⎝ \frac{1}{3} + \frac{1}{3^{2}} + \frac{1}{3^{3}} + \dots upto \infty ⎞ ⎠}

l

, then

l^{2}

is equal to

Q. If

\frac{9^{n} \times 3^{2} \times 3^{n} - (27)^{n}}{(3^{3}) \times 2^{3}} = \frac{1}{27}

, find the value of n.

Join BYJU'S Learning Program

Find the value of 33×32.

The correct options are A 35 D 243 Here the two terms have 33 and 32 have different exponents, but the same base.Hence by adding the powers we get, 33×32=33+2 = 35=243

Find the value of $3^{3} \times 3^{2}$ .

The correct options are
A
$3^{5}$

D
243

Here the two terms have $3^{3}$ and $3^{2}$ have different exponents, but the same base.Hence by adding the powers we get,

$3^{3} \times 3^{2} = 3^{3 + 2}$ = $3^{5} = 243$