Find the value of 3 sin-1 1-4 tan-1 -3-5cos-1-32-cos-11

= 3sin^ 1 4tan^ 1( √(3)) + 5cos. ( √(3)/2) + cos^ 1 (1) = 3× 90 4× 120^∘ + 5× 150^∘ +0^∘ = 270 480+750 #160; #160; #160; #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

General Solution of Trigonometric Equation

Find the valu...

Question

Find the value of $3 {sin}^{- 1} 1 - 4 {tan}^{- 1} (- \sqrt{3}) + 5 {cos}^{- 1} (- \frac{\sqrt{3}}{2}) + {cos}^{- 1} 1$

Open in App

Solution

Suggest Corrections

Similar questions

If $3 sin θ + 5 cos θ = 5$ , the value of $5 sin θ - 3 cos θ$ is

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

x y > 1

3 {s i n}^{- 1} \frac{2 x}{1 + x^{2}} - 4 {c o s}^{- 1} \frac{1 - x^{2}}{1 + x^{2}} + 2 {t a n}^{- 1} \frac{2 x}{1 - x^{2}} = \frac{π}{3}

s i n [(1 / 5) {c o s}^{- 1} x] = 1

{t a n}^{- 1} \sqrt{x^{2} + x} + {s i n}^{- 1} \sqrt{x^{2} + x + 1} = \frac{π}{2}

$c o s^{- 1} (- \frac{1}{2}) - 2 s i n^{- 1} (\frac{1}{2}) + 3 c o s^{- 1} (- \frac{1}{\sqrt{2}}) - 4 t a n^{- 1} (- 1)$ equals to

4 {cos}^{- 1} \frac{1}{2} + 2 {sin}^{- 1} \frac{1}{2} + 3 {tan}^{- 1} (- 1) + 2 {cos}^{- 1} (\frac{\sqrt{3}}{2})

3 {sin}^{- 1} (\frac{2 x}{1 + x^{2}}) - 4 {cos}^{- 1} (\frac{1 - x^{2}}{1 + x^{2}}) + 2 {tan}^{- 1} (\frac{2 x}{1 - x^{2}}) = \frac{π}{3}

x

Join BYJU'S Learning Program