Question

Find the value of ${35}^2+{47}^2$.

• A. $1454$
• B. $2834$
• C. $3434$
• D. $3439$

Answer 1

The correct option is C $3434$

35 ends with 5 so the last two digits will be 25 (_ _ 25)
The first two digits can be found as $3\times 4=12$
So, ${35}^2=1225$

${47}^2=(50-3{)}^2$
${47}^2=(50-3)\times (50-3)$
${47}^2=(50\times 50)+(50\times -3)+(-3\times 50)+\left(\right(-3)\times (-3\left)\right)$
${47}^2=2500-150-150+9$
${47}^2=2209$

$⟹{35}^2+{47}^2=1225+2209$
${35}^2+{47}^2=3434$