Find the value of $(3 m - 2 n) (2 m - 3 n)$ at $m = 1, n = - 1$

Open in App

Solution

$(3 m - 2 n) (2 m - 3 n)$
at $[m = 1]$ & $[n = - 1]$
now
$= [3 \times 1 - 2 (- 1)] [2 \times - 3 (- 1)]$
$[3 + 2] [2 + 3]$
$5 \times 5$
$= 25$

Suggest Corrections

Similar questions

\sum_{m = 1}^{\infty} \sum_{n = 1}^{\infty} \frac{m^{2} n}{3^{m} (n {.3}^{m} + m {.3}^{n})}

If $\frac{m + n}{m + 3 n} = \frac{2}{3}$ , find $\frac{2 n^{2}}{3 m^{+} m n}$

m = 2

n = 1

m + 3 n

Mark the correct option:

The value of (3^m)ⁿ, for every pair of integers (m, n), is

A. 3^m+n

B. 3^mn

D. 3^m + 3ⁿ

If 3m - 5m = -1 and 2m = n-3, find the value of (3m+5n) and (m+2n).

Join BYJU'S Learning Program