Find the value of $3 p (p^{2} + q^{2})$ at $p = 0, q = 1$

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Solution

The correct option is A $0$
We need to find value of $3 p (p^{2} + q^{2})$ at $p = 0, q = 1$
Therefore, $3 p (p^{2} + q^{2}) = 3 p^{3} + 3 p q^{2}$
Now, on substituting values of $p$ and $q$ , we get
$3 p^{2} + 3 p q^{2} = 3 (0)^{2} + 3 (0) (1)^{2}$
$= 0$

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