Question

Find the value of $3x^{2}y+6z^{2}x$, if $x=1,y=2,andz=1.$

• A. 27
• B. 15
• C. 11
• D. 12

Answer 1

The correct option is D 12

$3x^{2}y+6z^{2}x$
Substituting the value of $x=1,y=2,andz=1$ in the above expression,
$=3\left(1{)}^2\right(2)+6(1{)}^2\left(1\right)$
$=(3\times 1\times 2)+(6\times 1\times 1)$
$=6+6$
$=12$