Find the value of $4^{- 3}$ in fractional form:

Open in App

Solution

$4^{- 3} = \frac{1}{4^{3}} = \frac{1}{64}$

Suggest Corrections

Similar questions

Find the value of ${0.8}^{2}$ using fraction form.

\frac{1}{3}

\frac{2^{n + 4} - 2 (2^{n})}{2 (2^{n + 3})}

$(7 + 4 \sqrt{3})^{100}$ = I + f, where I is the integral part and f is the fractional part of

$(7 + 4 \sqrt{3})^{100}$ . Find the value of (I + f)(1 - f)

\frac{8}{5}, \frac{5}{8}, \frac{13}{2}

Join BYJU'S Learning Program