Question

Find the value of $4\cdot \cot {45}^o-{\sec }^2{60}^o+{\sin }^2{30}^o$

Answer 1

$4.\cot {45}^0-{\sec }^2{60}^0+{\sin }^2{30}^0$

$=4\times 1-{\left(2\right)}^2+{\left(\frac{1}{2}\right)}^2$

$=4-4+\frac{1}{4}$

$=\frac{1}{4}$