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Trigonometric Ratios of Compound Angles

Find the valu...

Question

Find the value of: $4 {cot}^{2} 45^{o} - {sec}^{2} 60^{o} + {csc}^{2} 30^{o} + cot 90^{o}$

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Solution

$4 {cot}^{2} 45^{o} - {sec}^{2} 60^{o} + {csc}^{2} 30^{o} + cot 90^{o}$
= $4 (1)^{2} - 2^{2} + 2^{2} + 0$
= $4 - 4 + 4$
= $4$

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x^{2} = {sin}^{2} 30^{o} + 4 {cot}^{2} 45^{o} - {sec}^{2} 60^{o}

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{cot}^{2} 30^{o} - 2 {cos}^{2} 60^{o} - \frac{3}{4} {sec}^{2} 45^{o} - {sin}^{2} 30^{o}

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Q. Find the value of:

{cos}^{2} 60^{o} + {sec}^{2} 30^{o}

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