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Question

Find the value of: (4)×(5)×16

A
320
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B
230
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C
-230
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D
-320
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Solution

The correct option is A 320
(4)×(5)×16
The product of 2 negative integres is a positive integer.
Hence (4)×(5)=+20
The product of 2 positive integers is a positive integer.
Hence +20×+16=320

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