Find the value of 493 - 504- using a suitable identity-

The correct option is C 248472493 × 504 =(500 7)× (500+4) Using the identity (x + a)(x + b) = x^2 + (a + b)x + (a)(b), Here x = 500, a = 4 and b = 7 =500^2 ...

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Byju's Answer

Standard VIII

Mathematics

Algebraic Identity: (x + a)(x + b) = x^2 + (a + b)x + ab

Find the valu...

Question

Find the value of $493 \times 504$ , using a suitable identity.

248500

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248528

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248472

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248448

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Solution

The correct option is C 248472
$493 \times 504$
= $(500 - 7) \times (500 + 4)$
Using the identity
$(x + a) (x + b) = x^{2} + (a + b) x + (a) (b)$ ,
Here $x = 500, a = 4$ and $b = - 7$
$= 500^{2} + (4 - 7) \times 500 + (4) (- 7)$
$= 250000 - 1500 - 28 = 248472$

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Find the value of 493×504, using a suitable identity.

The correct option is C 248472493×504 =(500−7)×(500+4) Using the identity (x+a)(x+b)=x2+(a+b)x+(a)(b), Here x=500,a=4 and b=−7 =5002+(4−7)×500+(4)(−7) =250000−1500−28=248472

Find the value of $493 \times 504$ , using a suitable identity.

The correct option is C 248472
$493 \times 504$
= $(500 - 7) \times (500 + 4)$
Using the identity
$(x + a) (x + b) = x^{2} + (a + b) x + (a) (b)$ ,
Here $x = 500, a = 4$ and $b = - 7$
$= 500^{2} + (4 - 7) \times 500 + (4) (- 7)$
$= 250000 - 1500 - 28 = 248472$