Question

Find the value of ${(4pq+3q)}^2-{(4pq-3q)}^2$.$\left[3Marks\right]$

Answer 1

${(4pq+3q)}^2-{(4pq-3q)}^2$

We have:

$(a+b{)}^2=a^2+2ab+b^2(a-b{)}^2=a^2-2ab+b^2$$\left[1.5Marks\right]$

So, ${(4pq+3q)}^2-{(4pq-3q)}^2$

$=[{\left(4pq\right)}^2+{\left(3q\right)}^2+2(4pq\left)\right(3q\left)\right]-[{\left(4pq\right)}^2+{\left(3q\right)}^2-2(4pq\left)\right(3q\left)\right]$
$=24p{q}^2+24p{q}^2$
$=48p{q}^2$$\left[1.5Marks\right]$