Question

Find the value of $4x^2-5x+3$ when $x=\frac{1}{2}$

Answer 1

$f\left(x\right)=4x^2-5x+3$

When $x=\frac{1}{2}$

$f\left(\frac{1}{2}\right)=4(\frac{1}{2}{)}^2-5(\frac{1}{2})+3$

$f\left(\frac{1}{2}\right)=4\left(\frac{1}{4}\right)-5\left(\frac{1}{2}\right)+3$

$f\left(\frac{1}{2}\right)=1-\frac{5}{2}+3$

$f\left(\frac{1}{2}\right)=\frac{3}{2}$

Hence $f\left(\frac{1}{2}\right)=\frac{3}{2}$