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Question

Find the value of 4x2+y2+25z2+4xy10yz20zx when x = 4, y = 3 and z = 2.

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Solution

x = 4, y = 3, z = 2

4x2+y2+25z2+4xy10yz20zx=(2x)2+(y)2+(5z)2+2×2x×y2×y×5z2×5z×2x=(2x+y5z)2=(2×4+35×2)2=(8+310)2=(1110)2=(1)2=1


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