Find the value of 4x2+y2+25z2+4xy−10yz−20zx when x = 4, y = 3 and z = 2.
x = 4, y = 3, z = 2
⇒ 4x2+y2+25z2+4xy−10yz−20zx=(2x)2+(y)2+(5z)2+2×2x×y−2×y×5z−2×5z×2x=(2x+y−5z)2=(2×4+3−5×2)2=(8+3−10)2=(11−10)2=(1)2=1