Find the value of 52- 42

The correct option is B 400 The given expression is 5^2 × 4^2 =5 × 5 × 4 × 4 =(5 × 4) × (5 × 4) =20 × 20 =400 ...

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Perfect Square Numbers

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Question

Find the value of $5^{2} \times 4^{2}$

200

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800

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400

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600

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Solution

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Similar questions

\frac{25}{k} = 1^{2} - \frac{2^{2}}{5} + \frac{3^{2}}{5^{2}} - \frac{4^{2}}{5^{3}} + \frac{5^{2}}{5^{4}} - \frac{6^{2}}{5^{2}} + . . . . . . \infty

k

2^{4} \times (- 3)^{2} \times 4^{2} \times (- 5)^{2}

A (x_{1}, y_{1}), B (x_{2}, y_{2}), C (x_{3}, y_{3})

(x_{1} - 4)^{2} + (y_{1} - 5)^{2} = (x_{2} - 4)^{2} + (y_{2} - 5)^{2} = (x_{3} - 4)^{2} + (y_{3} - 5)^{2},

(y_{1} + y_{2} + y_{3}) - (x_{1} + x_{2} + x_{3})

\frac{25}{k} = 1^{2} - \frac{2^{2}}{5^{2}} + \frac{2^{3}}{5^{3}} - \frac{4^{2}}{5^{4}} + \frac{2^{5}}{5^{5}} - \frac{2^{6}}{5^{6}} + . . . . . \infty

k

1^{2} - 2^{2} + 3^{2} - 4^{2} + 5^{2} - 6^{2} + . . . . + 99^{2} - 100^{2}

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