Find the value of $51^{2}$ .

2500

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2601

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2525

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2510

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Solution

The correct option is B 2601
Applying the identity
$(a + b)^{2} = (a^{2} + 2 a b + b^{2})$

$51^{2} = (50 + 1)^{2}$

$= (50^{2} + 2 \times 50 \times 1 + 1^{2})$

$= (2500 + 100 + 1) = 2601$

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Similar questions

Find the values of $(51)^{2}$ .

512 = 8^{3}

3.375 = {1.5}^{3}

\sqrt[3]{512} \times \sqrt[3]{3.375}

{(512)}^{- \frac{2}{9}}

(512)^{\frac{- 2}{9}}

513^{2} - 512^{2}

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