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Question
find the value of : 5sin2 + cos2 45`- 4tan2 30`/ 2sin30 cos30 + tan45
find the value of : 5sin2 + cos2 45`- 4tan2 30`/ 2sin30 cos30 + tan45
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Solution
Given 5sin^230+cos^245-4tan^230/2sin30°cos30°+tan45° = 5(1/2)^2 + (1/√2)^2 − 4(1/√3)^2/2(1/2)(√3/2) + 1 = (5/4) + (1/2) − (4/3) / (√3/2) + 1 = (15+6−16/12) / (√3+1)/2 = (5/12) / (√3+1)/2 = 5 / 6(√3+1)
= 5(1/2)^2 + (1/√2)^2 − 4(1/√3)^2/2(1/2)(√3/2) + 1
= (5/4) + (1/2) − (4/3) / (√3/2) + 1
= (15+6−16/12) / (√3+1)/2
= (5/12) / (√3+1)/2
= 5 / 6(√3+1)
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