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Question

Find the value of 5x[2x(x2+x3)x3]4x2÷x212x.

A
15x1212x4
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B
15x412x4
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C
15x4+12x4
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D
5x412x4
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Solution

The correct option is B 15x412x4
5x[2x(x2+x3)x3]4x2÷x212x
We need to follow BODMAS rule.
=> Brackets (parts of a calculation inside brackets always come first).
=> Orders (numbers involving powers or square roots).
=> Division.
=> Multiplication.
=> Addition.
=> Subtraction.
= 5x[2x(x2+x3)x3]4x2÷x212x
= 5x[2x3+2x4x3]4x2x212x
= 5x[x3+2x4]412x
= 5x4+10x412x4
= 15x412x4

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