Question

Find the value of $(64{)}^{-\frac{1}{3}}$

Answer 1

A) $(64{)}^{-1/3}$

$=(8\times 8{)}^{-1/3}$

$=(2\times 2\times 2\times 2\times 2\times 2{)}^{-1/3}$

$=(2^6{)}^{-1/3}$

$=(2{)}^{-6/3}$

$=(2{)}^{-2}$

$=\frac{1}{(2{)}^2}=\frac{1}{2\times 2}=\frac{1}{4}=0.25$

value of $(64{)}^{-1/3}=0.25$