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Question

Find the value of (6x6)×(2x2y3)×(24xy2)
(2 marks)

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Solution

(6x6)×(2x2y3)×(24xy2)
=[6×(2)×(24)]×(x6×x2×x)×(y3×y2) (1 mark)
Using the laws of indices, am×an=a(m+n).
=288×(x(6+2+1))×(y(3+2))
=288×x9×y5
=288x9y5 (1 mark)

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