Find the value of 6 x6 -2 x2 y3 -24 x y2- when x-1 and y-2-A- 8966B- 9216C- 9612D- 8536

The correct option is B 9216(6x^6)× ( 2x^2y^3)× ( 24xy^2) = [6× ( 2)× ( 24)]× (x^6× x^2× x)× (y^3× y^2) Using the laws of indices, a^m× a^n = a^(m+n). = 288× ( ...

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Standard VIII

Mathematics

Multiplication of Three or More Monomials

Find the valu...

Question

Find the value of $(6 x^{6}) \times (- 2 x^{2} y^{3}) \times (- 24 x y^{2})$ , when x = 1 and y = 2.

8966

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Solution

The correct option is B 9216
$(6 x^{6}) \times (- 2 x^{2} y^{3}) \times (- 24 x y^{2})$
$= [6 \times (- 2) \times (- 24)] \times (x^{6} \times x^{2} \times x) \times (y^{3} \times y^{2})$
Using the laws of indices, $a^{m} \times a^{n} = a^{(m + n)}$ .
$= 288 \times (x^{(6 + 2 + 1)}) \times (y^{(3 + 2)})$
$= 288 \times x^{9} \times y^{5}$
$= 288 x^{9} y^{5}$
Substituting the value of x = 1 and y = 2 in the above expression, we get
$= 288 \times (1)^{9} \times (2)^{5}$
$= 288 \times 1 \times 32$
= 9216

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Find the value of (6x6)×(−2x2y3)×(−24xy2), when x = 1 and y = 2.

Find the value of $(6 x^{6}) \times (- 2 x^{2} y^{3}) \times (- 24 x y^{2})$ , when x = 1 and y = 2.