Question

Find the value of:
$(8^0-2^0)\times (8^0+2^0)$.

• A. 1
• B. 0.0
• C. 6
• D. 36

Answer 1

The correct option is B 0.0

We know for any non-zero integer 'a',
$a^0=1$.
So,
$(8^0-2^0)\times (8^0+2^0)$
$=(1-1)\times (1+1)=0\times 2=0$