Find the value of -8-2-8-3

The correct options are B 1/( 8)^5 C ( 8)^ 5By the Laws of Exponents, we know that a^m× a^n=a^m+n ⇒( 8)^ 2×( 8)^ 3 =( 8)^( 2)+( 3) =( 8)^ 5=1/( 8)^5 ...

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Byju's Answer

Standard VII

Mathematics

Multiplying Terms with the Same Base

Find the valu...

Question

Find the value of $(- 8)^{- 2} \times (- 8)^{- 3}$

(- 8)^{5}

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\frac{1}{(- 8)^{5}}

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(- 8)^{- 5}

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\frac{1}{(8)^{5}}

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Solution

The correct options are
B $\frac{1}{(- 8)^{5}}$
C $(- 8)^{- 5}$
By the Laws of Exponents, we know that $a^{m} \times a^{n} = a^{m + n}$
$\Rightarrow (- 8)^{- 2} \times (- 8)^{- 3} = (- 8)^{(- 2) + (- 3)} = (- 8)^{- 5} = \frac{1}{(- 8)^{5}}$

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Find the value of (−8)−2×(−8)−3

The correct options are B 1(−8)5 C (−8)−5By the Laws of Exponents, we know that am×an=am+n ⇒(−8)−2×(−8)−3=(−8)(−2)+(−3)=(−8)−5=1(−8)5

Find the value of $(- 8)^{- 2} \times (- 8)^{- 3}$

The correct options are
B $\frac{1}{(- 8)^{5}}$
C $(- 8)^{- 5}$
By the Laws of Exponents, we know that $a^{m} \times a^{n} = a^{m + n}$
$\Rightarrow (- 8)^{- 2} \times (- 8)^{- 3} = (- 8)^{(- 2) + (- 3)} = (- 8)^{- 5} = \frac{1}{(- 8)^{5}}$