Find the value of $81^{\frac{1}{2}}$ .

Open in App

Solution

$81^{\frac{1}{2}}$

$= (9^{2})^{\frac{1}{2}}$

$= 9^{2 \times \frac{1}{2}} = 9$

Suggest Corrections

Similar questions

(81^{1 / 2} \times 8^{2 / 3} \times 32^{2 / 5})^{1 / 2}

81^{\frac{1}{{log}_{5} 3}}

81^{\frac{1}{3}} \times 576^{\frac{1}{3}}

Find the value of

$(i) 81^{\frac{1}{3}} \times 576^{\frac{1}{3}}$

$(i i) 64^{- \frac{2}{3}} \times 27^{- \frac{2}{3}}$

3^{\frac{4}{{log}_{2} 9}} + 27^{\frac{1}{{log}_{49} 9}} + 81^{\frac{1}{{log}_{4} 3}}

Join BYJU'S Learning Program