Find the value of 8sin 2x cos 4x sin 6x, when x = $15^{\circ}$

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Solution

At x= $15^{\circ}$
8 sin 2x cos 4x sin 6x = 8 sin $30^{\circ} cos 60^{\circ} sin 90^{\circ}$
$8 \times \frac{1}{2} \times \frac{1}{2} \times 1 = 2$

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