Question

Find the value of $(-8u^2{v}^6)\times (-20uv)$ for $u=2.5$ and $v=1$.

Answer 1

Given expression $=(-8u^2{v}^6)\times (-20uv)$
Grouping the like terms, we get
$=(-8)\times (-20)\times u^2\times u\times v^6\times v$
Substitute $u=2.5$ and $v=1$ in above expression, we get
$=160\times (2.5{)}^2\times (2.5)\times 1^6\times 1$
$=160\times 6.25\times 2.5\times 1\times 1$
$=160\times 15.625$
$=2500$
Hence, the value of the given expression is $2500$