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Question

Find the value of 8x3y3, if 2xy=12 and xy=4.

A
2016
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B
2017
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C
2018
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D
2019
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Solution

The correct option is A 2016
2xy=12 and xy=4

8x3y3=(2x)3y3
=(2xy)((2x)2+y2+2xy) [Using a3b3=(ab)(a2+b2+ab)]

=(2xy)[(2xy)2+2×2x×y+2xy]
[Using a2+b2=(ab)2+2ab]

=(2xy)[(2xy)2+6xy]

On substituting the values, 2xy=12 and xy=4, we get,
=12×[(12)2+6(4)]
=12[144+24]
=12×168=2016

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