Question

Find the value of ${\left(997\right)}^2$ using algebraic identities.

• A. 994009
• B. 996009
• C. 940009
• D. 946009

Answer 1

The correct option is A 994009

We can write ${\left(997\right)}^2$ as ${(1000-3)}^2$.

We know that ${(a-b)}^2=a^2+b^2-2ab$.

Hence $(1000-3{)}^2=(1000{)}^2+(3{)}^2-2(1000\left)\right(3)$
= 1000000 + 9 - 6000 = 994009