Question

Find the value of $(998{)}^2$.$\left[2Marks\right]$

Answer 1

Using the identity, $(a-b{)}^2=a^2-2ab+b^2$,$\left[0.5Mark\right]$
we have,
$(998{)}^2=(1000-2{)}^2$
$=(1000{)}^2-2\times 1000\times 2+2^2$
= 9,96,004$\left[1.5Marks\right]$