Find the value of ( 9a + 10b)2
9a2 + 180ab + 10b2
81a2 + 180ab + 100b2
81a2 + 90ab + 100b2
81a + 180ab + 100b
By using square identity (a+b)2 = a2 +b2+2ab, we get
(9a+10b)2 = 81a2 + 180ab + 100b2
If log3x=a, find the value of 81a−1 in terms of x.
Find the value of : (3a−12)(3a−12)