Question

Find the value of $a^0{b}^2$, if a=4 and b=-3.

• A. 9
• B. -9
• C. $\frac{1}{9}$
• D. $\frac{-1}{9}$

Answer 1

The correct option is A 9

By the Laws of Exponents, we know that $a^0=1$.
Now, putting the values of a and b in $a^0{b}^2$, we get
$4^0\times (-3{)}^2=1\times (-3{)}^2=(-3{)}^2=(-3)\times (-3)=9$
Therefore, the value of $a^0{b}^2=9$