Find the value of a3−b3−3a2b+3ab2 , when a = 4 and b = 3.
1
12
21
None of these
We have to substitute the value of a = 4 and b = 3 in the expression.
a3−b3−3a2b+3ab2
=(4)3+(3)3−3(4)2×3+3×4(32)=64−27−3×16×3+3×4×9
= 175 – 174
= 1