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Question

Find the value of a3b33a2b+3ab2 , when a = 4 and b = 3.


A

1

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B

12

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C

21

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D

None of these

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Solution

The correct option is A

1


We have to substitute the value of a = 4 and b = 3 in the expression.

a3b33a2b+3ab2

=(4)3+(3)33(4)2×3+3×4(32)=64273×16×3+3×4×9

= 175 – 174

= 1


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